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If H.C.F. of $135x^2$ and $189x^3$ is $108$, then find the value of $x$.
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Solution:
$135x^2 = 3^3 \times 5 \times x^2$, $189x^3 = 3^3 \times 7 \times x^3$ (1 Mark)
HCF($135x^2$, $189x^3$) = $27x^2$
$27x^2 = 108 \Rightarrow x = 2$ (1 Mark)
$135x^2 = 3^3 \times 5 \times x^2$, $189x^3 = 3^3 \times 7 \times x^3$ (1 Mark)
HCF($135x^2$, $189x^3$) = $27x^2$
$27x^2 = 108 \Rightarrow x = 2$ (1 Mark)