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If $a = 2^2 \times 3^x$, $b = 2^2 \times 3 \times 5$, $c = 2^2 \times 3 \times 7$ and LCM $(a, b, c) = 3780$, then $x$ is equal to
- (a)$1$
- (b)$2$
- (c)$3$
- (d)$0$
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(C) $3$
If a = 22 × 3x , b = 22 × 3 × 5 , c = 22 × 3 × 7 and LCM (a, b, c) = 3780 , then x is equal to
CBSE Class 10 Maths PYQ · Real Numbers · Find lcm & hcf · 1 Mark · March 2024 · Standard
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