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Given HCF $(2520, 6600) = 40$, LCM $(2520, 6600) = 252 \times k$, then the value of $k$ is:
- (a)$1650$
- (b)$165$
- (c)$1600$
- (d)$1625$
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(A) $1650$
Given HCF (2520, 6600) = 40 , LCM (2520, 6600) = 252 × k , then the value of k is: (A) 1650 (C) 165 (B) 1600 (D) 1625
CBSE Class 10 Maths PYQ · Real Numbers · Find lcm & hcf · 1 Mark · March 2024 · Standard
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