73
Find the smallest $5$-digit number exactly divisible by $24$ and $36$.
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Solution:
LCM : $(24, 36) = 72$ (1 Mark)
(for division steps to find remainder $64$) (1/2 Mark)
$\therefore$ Required number is $10000 + 72 – 64 = 10008$ (1/2 Mark)
LCM : $(24, 36) = 72$ (1 Mark)
(for division steps to find remainder $64$) (1/2 Mark)
$\therefore$ Required number is $10000 + 72 – 64 = 10008$ (1/2 Mark)