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Solve the quadratic equation $\sqrt{3}x^2 + 10x + 7\sqrt{3} = 0$ using quadratic formula.
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Discriminant $= 16$
$x = \frac{-10 \pm \sqrt{16}}{2\sqrt{3}}$
$x = -\frac{3}{\sqrt{3}}, -\frac{7}{\sqrt{3}}$ or $x = -\sqrt{3}, -\frac{7}{3}\sqrt{3}$
$x = \frac{-10 \pm \sqrt{16}}{2\sqrt{3}}$
$x = -\frac{3}{\sqrt{3}}, -\frac{7}{\sqrt{3}}$ or $x = -\sqrt{3}, -\frac{7}{3}\sqrt{3}$