Find the nature of roots of the equation 4x2 - 4a2x + a4 - b4 = 0, b ≠ 0

CBSE Class 10 Maths PYQ · Quadratic Equations · Find roots · 2 Marks · March 2025 · Basic

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922 Marks · March 2025 · Basic
Find the nature of roots of the equation $4x^2 - 4a^2x + a^4 - b^4 = 0, b \neq 0$
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Discriminant $= (-4a^2)^2 - 4 \times 4 \times (a^4 - b^4) = 16b^4$
Since, Discriminant $> 0$
Therefore, the given equation has real and distinct roots
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