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Two dice are thrown at the same time. Determine the probability that the difference of the numbers on the two dice is $2$.
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Total outcomes $= 36$.
Outcomes with difference $2 = 8$
$ $(1,3), (3,1), (4,2), (2,4), (5,3), (3,5), (4,6), (6,4)$.$
$P(\text{difference is } 2) = \frac{8}{36} = \frac{2}{9}$.
Outcomes with difference $2 = 8$
$ $(1,3), (3,1), (4,2), (2,4), (5,3), (3,5), (4,6), (6,4)$.$
$P(\text{difference is } 2) = \frac{8}{36} = \frac{2}{9}$.