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A die is thrown twice. Find the probability that $5$ will come up atleast once.
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Total outcomes $= 36$
Favourable outcomes : $(1,5) (2, 5) (3,5) (4,5) (5,5) (6,5) (5,1) (5,2) (5,3) (5,4) (5,6)$
$P(5 \text{ will come at least once}) = \frac{11}{36}$
Favourable outcomes : $(1,5) (2, 5) (3,5) (4,5) (5,5) (6,5) (5,1) (5,2) (5,3) (5,4) (5,6)$
$P(5 \text{ will come at least once}) = \frac{11}{36}$