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Two dice are rolled together. Find the probability that at least one of the numbers obtained is a multiple of $3$.
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Solution: Total number of outcomes = $36$ (1)
Number of favourable outcomes = $20$ (1)
P( at least one of the numbers obtained is multiple of $3$) = $\frac{20}{36}$ or $\frac{5}{9}$ (1)
Number of favourable outcomes = $20$ (1)
P( at least one of the numbers obtained is multiple of $3$) = $\frac{20}{36}$ or $\frac{5}{9}$ (1)