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Two dice are rolled together. Find the probability that (i) in the obtained outcomes one number is twice the another. (ii) both the numbers obtained are greater than $4$.
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Solution: (i) P ( one number is twice the other) = $\frac{6}{36}$ or $\frac{1}{6}$ (1
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(ii) P (both the numbers obtained are greater than $4$) = $\frac{4}{36}$ or $\frac{1}{9}$ (1
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textonehalf Mark)
(ii) P (both the numbers obtained are greater than $4$) = $\frac{4}{36}$ or $\frac{1}{9}$ (1
textonehalf Mark)