51
A game of chance consists of spinning a wheel which comes to rest at one of the numbers from $1$ to $10$ (as shown in the given figure) with equal probabilities.
What is the probability that the wheel stops at
(i) a prime number greater than $2$ ?
(ii) an odd number less than $9$ ?
(iii) a multiple of $4$ ?
What is the probability that the wheel stops at
(i) a prime number greater than $2$ ?
(ii) an odd number less than $9$ ?
(iii) a multiple of $4$ ?
Show SolutionHide Solution↓
Solution: (i) $P(\text{a prime number greater than } 2) = \frac{3}{10}$ [1 mark]
(ii) $P(\text{an odd number less than } 9) = \frac{4}{10}$ or $\frac{2}{5}$ [1 mark]
(iii) $P(\text{a multiple of } 4) = \frac{2}{10}$ or $\frac{1}{5}$ [1 mark]
(ii) $P(\text{an odd number less than } 9) = \frac{4}{10}$ or $\frac{2}{5}$ [1 mark]
(iii) $P(\text{a multiple of } 4) = \frac{2}{10}$ or $\frac{1}{5}$ [1 mark]