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A box contains $90$ discs, numbered from $1$ to $90$. If one disc is drawn at random from the box, the probability that it bears a prime number less than $23$ is
- (a)$\frac{7}{90}$
- (b)$\frac{1}{9}$
- (c)$\frac{4}{45}$
- (d)$\frac{9}{89}$
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(C) $\frac{4}{45}$