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A die is thrown twice. What is the probability that (i) difference between two numbers obtained is 3? (ii) sum of the numbers obtained is 8?
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(i) $P(\text{difference between two numbers obtained is 3}) = \frac{6}{36}$ or $\frac{1}{6}$ [$1$ mark]
(ii) $P(\text{sum of numbers obtained is 8}) = \frac{5}{36}$ [$1$ mark]
(ii) $P(\text{sum of numbers obtained is 8}) = \frac{5}{36}$ [$1$ mark]