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A box contains 120 discs, which are numbered from 1 to 120. If one disc is drawn at random from the box, find the probability that
(i) it bears a 2-digit number
(ii) the number is a perfect square.
(i) it bears a 2-digit number
(ii) the number is a perfect square.
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(i) $P(\text{2-digit number}) = \frac{90}{120} \text{ or } \frac{3}{4}$ (1 mark)
(ii) $P(\text{the number is a perfect square}) = \frac{10}{120} \text{ or } \frac{1}{12}$ (1 mark)
(ii) $P(\text{the number is a perfect square}) = \frac{10}{120} \text{ or } \frac{1}{12}$ (1 mark)