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If $\alpha$, $\beta$ are the zeroes of the polynomial $p(x) = x^2-3x-1$, then find the value of $\frac{1}{\alpha} + \frac{1}{\beta}$.
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Here, $\alpha + \beta = 3$, $\alpha\beta = -1$ (1 Mark)
$\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha+\beta}{\alpha\beta} = \frac{3}{-1}$ (1/2 Mark)
$= -3$ (1/2 Mark)
$\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha+\beta}{\alpha\beta} = \frac{3}{-1}$ (1/2 Mark)
$= -3$ (1/2 Mark)