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Find the zeroes of the quadratic polynomial $x^2+7x+10$, and verify the relationship between the zeroes and its coefficients.
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$x^2 + 7x + 10 = (x + 2)(x + 5)$ (1 Mark)
So, the zeroes of the polynomial are $-2$ and $-5$ (1/2 Mark)
Sum of zeroes $= -7 = \frac{-7}{1} = \frac{\text{coefficient of } x}{\text{coeffiecient of } x^2}$ (1/2 Mark)
Product of zeroes $= 10 = \frac{10}{1} = \frac{\text{constant term}}{\text{coefficient of } x^2}$ (1/2 Mark)
So, the zeroes of the polynomial are $-2$ and $-5$ (1/2 Mark)
Sum of zeroes $= -7 = \frac{-7}{1} = \frac{\text{coefficient of } x}{\text{coeffiecient of } x^2}$ (1/2 Mark)
Product of zeroes $= 10 = \frac{10}{1} = \frac{\text{constant term}}{\text{coefficient of } x^2}$ (1/2 Mark)