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Find a quadratic polynomial whose zeroes are $2$ and $-\frac{7}{5}$
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Sum of zeroes $= 2 + \left(-\frac{7}{5}\right) = \frac{3}{5}$ ($1/2$ mark)
Product of zeroes $= 2 \times \left(-\frac{7}{5}\right) = -\frac{14}{5}$ ($1/2$ mark)
$\therefore$ Required quadratic polynomial is $x^2 - \frac{3}{5}x - \frac{14}{5}$ or $5x^2 - 3x - 14$ ($1$ mark)
Product of zeroes $= 2 \times \left(-\frac{7}{5}\right) = -\frac{14}{5}$ ($1/2$ mark)
$\therefore$ Required quadratic polynomial is $x^2 - \frac{3}{5}x - \frac{14}{5}$ or $5x^2 - 3x - 14$ ($1$ mark)