100
Find a quadratic polynomial whose sum of the zeroes is $8$ and difference of the zeroes is $2$.
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Let the zeroes be $\alpha$ and $\beta$
$\therefore \alpha + \beta = 8$ and $\alpha - \beta = 2$
Solving above two equations, we get $\alpha = 5$ and $\beta = 3$
So, the quadratic polynomial is $x^2 - 8x + 15$
$\therefore \alpha + \beta = 8$ and $\alpha - \beta = 2$
Solving above two equations, we get $\alpha = 5$ and $\beta = 3$
So, the quadratic polynomial is $x^2 - 8x + 15$