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Find the ratio in which the line segment joining the points $A(6, 3)$ and $B(-2, -5)$ is divided by $x$-axis.
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Let $P(x, 0)$ be the point on $x$ axis which divides $AB$ in the ratio $k : 1$
$\frac{-5k + 3}{k+1} = 0 \Rightarrow k = \frac{3}{5}$
Ratio is $3:5$
$\frac{-5k + 3}{k+1} = 0 \Rightarrow k = \frac{3}{5}$
Ratio is $3:5$