100
Find the coordinates of the points of trisection of line segment joining the points $(-4, 1)$ and $(6, 5)$.
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$AP : PB = 1 : 2$
$\therefore x_1 = \frac{-8+6}{3} = \frac{-2}{3}, y_1 = \frac{5+2}{3} = \frac{7}{3}$
Coordinates of point $P$ are $(\frac{-2}{3}, \frac{7}{3})$
$AQ : QB = 2 : 1$
$\therefore x_2 = \frac{12-4}{3} = \frac{8}{3}, y_2 = \frac{10+1}{3} = \frac{11}{3}$
Coordinates of point $Q$ are $(\frac{8}{3}, \frac{11}{3})$
$\therefore x_1 = \frac{-8+6}{3} = \frac{-2}{3}, y_1 = \frac{5+2}{3} = \frac{7}{3}$
Coordinates of point $P$ are $(\frac{-2}{3}, \frac{7}{3})$
$AQ : QB = 2 : 1$
$\therefore x_2 = \frac{12-4}{3} = \frac{8}{3}, y_2 = \frac{10+1}{3} = \frac{11}{3}$
Coordinates of point $Q$ are $(\frac{8}{3}, \frac{11}{3})$