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In the given figure, PA is a tangent from an external point P to a circle with centre O. If $\angle POB = 125^\circ$, then $\angle APO$ is equal to :
- (a)$25^\circ$
- (b)$65^\circ$
- (c)$90^\circ$
- (d)$35^\circ$
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(d) $35^\circ$ (1 Mark)