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In the given figure, PA and PB are tangents to a circle centred at O. If $\angle OAB = 15^\circ$, then $\angle APB$ equals :
- (a)$30^\circ$
- (b)$15^\circ$
- (c)$45^\circ$
- (d)$10^\circ$
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Sol. (A) $30^\circ$ (1 Mark)
In the given figure, PA and PB are tangents to a circle centred at O. If ∠ OAB = 15° , then ∠ APB equals :
CBSE Class 10 Maths PYQ · Circles · Find angles · 1 Mark · March 2026 · Standard
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