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In the given figure, $AC$ and $AB$ are tangents to a circle centered at $O$. If $\angle COD = 120^{\circ}$, then $\angle BAO$ is equal to :

- (a)$30^{\circ}$
- (b)$60^{\circ}$
- (c)$45^{\circ}$
- (d)$90^{\circ}$
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(a) $30^{\circ}$