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In the given figure, $AB$ is a tangent to the circle centered at $O$. If $OA = 6$ cm and $\angle OAB = 30^{\circ}$, then the radius of the circle is :
- (a)$3$ cm
- (b)$3\sqrt{3}$ cm
- (c)$2$ cm
- (d)$\sqrt{3}$ cm
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(a) $3$ cm