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In the given figure, AB and CD are diameters of a circle with centre O perpendicular to each other. If OA = $7$ cm, find the area of shaded region.
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Area of quadrant BOC = $\frac{1}{4} \times \frac{22}{7} \times 7 \times 7 = \frac{77}{2}$ cm$^2$
Area of $\triangle BOC = \frac{1}{2} \times OB \times OC = \frac{1}{2} \times 7 \times 7 = \frac{49}{2}$ cm$^2$
Area of shaded region = $2 [\frac{77}{2} - \frac{49}{2}] = 28$ cm$^2$
Area of $\triangle BOC = \frac{1}{2} \times OB \times OC = \frac{1}{2} \times 7 \times 7 = \frac{49}{2}$ cm$^2$
Area of shaded region = $2 [\frac{77}{2} - \frac{49}{2}] = 28$ cm$^2$