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If $\triangle$ ABC $\sim \triangle$ PQR in which AB = $6$ cm, BC = $4$ cm, AC = $8$ cm and PR = $6$ cm, then find the length of (PQ + QR).
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$\frac{6}{\text{PQ}} = \frac{4}{\text{QR}} = \frac{8}{6}$ (1/2)
$\Rightarrow \text{PQ} = \frac{9}{2}$ cm or $4.5$ cm (1/2)
and QR = $3$ cm (1/2)
$\therefore$ PQ + QR = $7.5$cm (1/2)
$\Rightarrow \text{PQ} = \frac{9}{2}$ cm or $4.5$ cm (1/2)
and QR = $3$ cm (1/2)
$\therefore$ PQ + QR = $7.5$cm (1/2)