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Find the area of the sector of a circle of radius 42 cm and of central angle $30^\circ$. Also, find the area of the corresponding major sector. [Use $\pi = \frac{22}{7}$]
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Area of minor sector = $\frac{30}{360} \times \frac{22}{7} \times 42 \times 42$ (1 Mark)
= $462 \text{ cm}^2$ (1/2 Mark)
Angle of corresponding major sector = $330^\circ$ (1/2 Mark)
Area of Major Sector = $\frac{330}{360} \times \frac{22}{7} \times 42 \times 42$ (1/2 Mark)
= $5082 \text{ cm}^2$ (1/2 Mark)
= $462 \text{ cm}^2$ (1/2 Mark)
Angle of corresponding major sector = $330^\circ$ (1/2 Mark)
Area of Major Sector = $\frac{330}{360} \times \frac{22}{7} \times 42 \times 42$ (1/2 Mark)
= $5082 \text{ cm}^2$ (1/2 Mark)