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A circle of diameter $20$ cm is equally divided into five sectors. Find the area and perimeter of one of the sectors.
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Sol. Here, radius = $10$ cm
Central angle of each sector = $\frac{360^\circ}{5} = 72^\circ$ (I Mark)
Area of one sector = $\frac{72}{360} \times \frac{22}{7} \times 10 \times 10$ (II Mark)
$= \frac{440}{7}$ cm$^2$ or $62.8$ cm$^2$ (approx.) (III Mark)
Perimeter of one sector = $\frac{72}{360} \times 2 \times \frac{22}{7} \times 10 + 10 + 10$ (IV Mark)
$= \frac{228}{7}$ cm or $32.5$ cm (approx.) (V Mark)
Central angle of each sector = $\frac{360^\circ}{5} = 72^\circ$ (I Mark)
Area of one sector = $\frac{72}{360} \times \frac{22}{7} \times 10 \times 10$ (II Mark)
$= \frac{440}{7}$ cm$^2$ or $62.8$ cm$^2$ (approx.) (III Mark)
Perimeter of one sector = $\frac{72}{360} \times 2 \times \frac{22}{7} \times 10 + 10 + 10$ (IV Mark)
$= \frac{228}{7}$ cm or $32.5$ cm (approx.) (V Mark)