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Area of a segment of a circle of radius '$r$' and central angle $60^\circ$ is:
- (a)$\frac{\pi r^2}{2} - \frac{1}{2} r^2$
- (b)$\frac{2\pi r}{4} - \frac{\sqrt{3}}{4} r^2$
- (c)$\frac{\pi r^2}{6} - \frac{\sqrt{3}}{4} r^2$
- (d)$\frac{2\pi r}{4} - r^2 \sin 60^\circ$
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Sol. (C) $\frac{\pi r^2}{6} - \frac{\sqrt{3}}{4} r^2$ (1 Mark)