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A chord is subtending an angle of $90^\circ$ at the centre of a circle of radius $14$ cm. Find the area of the corresponding minor segment of the circle.
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Area of minor segment $= \pi\times 14^2 \times \frac{90}{360} - \frac{1}{2} \times 14^2$
$= (154 - 98) = 56$
Hence, area of minor segment $= 56$ cm$^2$
$= (154 - 98) = 56$
Hence, area of minor segment $= 56$ cm$^2$