A chord of a circle of radius 10 cm subtends a right angle at the centre of the circle. Find the area of the…
CBSE Class 10 Maths PYQ · Areas Related to Circles · Segment Area · 3 Marks · March 2025 · Standard
Solve it yourself first — then press ↓ or tap Show Solution. Use ←→ for previous / next question.
503 Marks · March 2025 · Standard
A chord of a circle of radius $10 \operatorname{cm}$ subtends a right angle at the centre of the circle. Find the area of the corresponding minor segment. [Use $\pi = 3.14$]
Show SolutionHide Solution↓
Sol. Area of minor segment ACB $=$ Area of sector OACB $-$ Area of right $\triangle OAB$ Area of sector OACB $= \frac{90}{360} \times 3.14 \times 10 \times 10$ $= 78.5 \operatorname{cm}^2$ Area of right $\triangle OAB = \frac{1}{2} \times 10 \times 10$ $= 50 \operatorname{cm}^2$ Area of minor segment ACB $= (78.5 - 50)$ $= 28.5 \operatorname{cm}^2$
