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$\frac{\text{sin}^3 A + \text{cos}^3 A}{\text{sin } A + \text{cos } A} + \text{sin } A \text{cos } A$ on simplification gives :
- (a)$1$
- (b)$2$
- (c)$1 + 2 \text{sin } A \text{cos } A$
- (d)$0$
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Sol. (A) $1$
sin3 A + cos3 Asin A + cos A + sin A cos A on simplification gives :
CBSE Class 10 Maths PYQ · Trigonometry · Prove Given Result · 1 Mark · July 2024 · Standard
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