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If $\triangle$ ABC is right-angled at C, then the value of $\cos (A + B)$ is :
- (a)$1$
- (b)$\frac{1}{2}$
- (c)$\frac{\sqrt{3}}{2}$
- (d)$0$
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(D) $0$
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · July 2025 · Standard
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