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If $5 \tan \theta - 12 = 0$, then the value of $\sin \theta$ is :
- (a)$\frac{5}{12}$
- (b)$\frac{5}{13}$
- (c)$\frac{12}{13}$
- (d)$\frac{12}{5}$
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(B) $\frac{12}{13}$
If 5 θ - 12 = 0 , then the value of θ is :
CBSE Class 10 Maths PYQ · Trigonometry · Find T-ratio or value of Expression · 1 Mark · March 2024 · Standard
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