27
If $\sin \theta + \cos \theta = \sqrt{2} \cos \theta$, $(\theta \neq 90^\circ)$, then $\tan \theta$ is equal to
- (a)$\sqrt{2} + 1$
- (b)$\sqrt{2} - 1$
- (c)$-\sqrt{2}$
- (d)$\sqrt{2}$
Show SolutionHide Solution↓
(B) $\sqrt{2} - 1$
If θ + θ = √2 θ , (θ ≠ 90°) , then θ is equal to
CBSE Class 10 Maths PYQ · Trigonometry · Properties of T-ratio · 1 Mark · March 2025 · Standard
Solve it yourself first — then press ↓ or tap Show Solution. Use ← → for previous / next question.