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Evaluate : $\frac{1-2 \tan^2 30^\circ - \sec^2 45^\circ}{\sin^2 60^\circ}$
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$= \frac{1-2\times(\frac{1}{\sqrt{3}})^2-(\sqrt{2})^2}{(\frac{\sqrt{3}}{2})^2}$ (I) (1½ Mark)
$= -\frac{20}{9}$ (II) (1/2 Mark)
$= -\frac{20}{9}$ (II) (1/2 Mark)