Sides AB , BC and the median AD of △ ABC are respectively proportional to sides PQ , QR and the median PM of another △…

Correct figure
$$\begin{aligned}& \therefore \frac{AB}{PQ} = \frac{BC}{QR} = \frac{AD}{PM} \\ & \therefore \frac{AB}{PQ} = \frac{2BD}{2QM} = \frac{AD}{PM} \\ & \Rightarrow \frac{AB}{PQ} = \frac{BD}{QM} = \frac{AD}{PM}-------(i) \\ & \Rightarrow \triangle ABD \sim \triangle PQM \\ & \Rightarrow \angle B = \angle Q_ -----(ii) \\ & \text{In } \triangle ABC \text{ and } \triangle PQR \\ & \frac{AB}{PQ} = \frac{BC}{QR} \\ & \angle B = \angle Q \\ & \therefore \triangle ABC \sim \triangle PQR\end{aligned}$$