136
It is given that $\Delta ACD \cong \Delta ABE$. Prove that $\Delta ADE \sim \Delta ABC$.
Show SolutionHide Solution↓
Solution: Given, $\Delta ACD \cong \Delta ABE, \therefore$ by CPCT
$AC = AB$ and $AD = AE$
$\Rightarrow \frac{AB}{AD} = \frac{AC}{AE}$ and $\angle A$ is common
Hence, by SAS similarity criterion
$\Delta ADE \sim \Delta ABC$
$AC = AB$ and $AD = AE$
$\Rightarrow \frac{AB}{AD} = \frac{AC}{AE}$ and $\angle A$ is common
Hence, by SAS similarity criterion
$\Delta ADE \sim \Delta ABC$