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In the given figure, $\triangle ODC \sim \triangle OBA$. If $\angle BOC = 110\degree$, $\angle ODC = 45\degree$ and $AB = 2 CD$, then find (i) $m\angle OAB$ (ii) $OB:OD$.
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Solution:
(i) $\triangle ODC \sim \triangle OBA$
Getting $m\angle OAB = 65\degree$ (1 Mark)
(ii) $\frac{OD}{OB} = \frac{DC}{BA} = \frac{1}{2}$
$OB:OD = 2:1$ (1 Mark)
(i) $\triangle ODC \sim \triangle OBA$
Getting $m\angle OAB = 65\degree$ (1 Mark)
(ii) $\frac{OD}{OB} = \frac{DC}{BA} = \frac{1}{2}$
$OB:OD = 2:1$ (1 Mark)