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In the given figure, in $\triangle ABC$, $AD \perp BC$ and $\angle BAC = 90^{\circ}$. If $BC = 16 \operatorname{cm}$ and $DC = 4 \operatorname{cm}$, then the value of $x$ is :

- (a)$4 \operatorname{cm}$
- (b)$5 \operatorname{cm}$
- (c)$8 \operatorname{cm}$
- (d)$3 \operatorname{cm}$
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Sol. (C) $8 \operatorname{cm}$