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In the given figure, if $PQ \parallel RS$, then prove that $\Delta POQ \sim \Delta SOR$.
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Solution : (a) As $PQ \parallel RS$
$\angle P = \angle S$
$\angle Q = \angle R$ (Alternate interior angles)
$\therefore \Delta POQ \sim \Delta SOR$ (by AA similarity criterion)
$\angle P = \angle S$
$\angle Q = \angle R$ (Alternate interior angles)
$\therefore \Delta POQ \sim \Delta SOR$ (by AA similarity criterion)