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In the given figure, if $\Delta ACP \sim \Delta DCP$, then :
- (a)$\angle DCP = 60^{\circ}$
- (b)$\angle DCP = 30^{\circ}$
- (c)$\angle DCP = 90^{\circ}$
- (d)$\angle DPC = 30^{\circ}$
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Ans: (B) $\angle DCP =30^{\circ}$
In the given figure, if ACP DCP , then :
CBSE Class 10 Maths PYQ · Triangles · Similarity with Triangles · 1 Mark · March 2026 · Basic
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