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In the given figure, $DE \parallel BC$. If $\frac{AD}{DB} = \frac{1}{3}$ and $AC = 6$ cm, then length AE is
- (a)$1.5$ cm
- (b)$2$ cm
- (c)$1$ cm
- (d)$3$ cm
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(A) $1.5$ cm
In the given figure, DE BC . If AD/DB = 1/3 and AC = 6 cm, then length AE is
CBSE Class 10 Maths PYQ · Triangles · BPT & Converse · 1 Mark · March 2026 · Standard
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