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In the adjoining figure, $AP = 1$ cm, $BP = 2$ cm, $AQ = 1.5$ cm and $AC = 4.5$ cm. Prove that $\Delta APQ \sim \Delta ABC$. Hence find the length of $PQ$, if $BC = 3.6$ cm.

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$\frac{AP}{AB} = \frac{1}{3}$; $\frac{AQ}{AC} = \frac{1.5}{4.5} = \frac{1}{3}$
$\angle ACP = \angle ACB$
$\Delta APQ \sim \Delta ABC$
$PQ = 1.2$ cm
$\angle ACP = \angle ACB$
$\Delta APQ \sim \Delta ABC$
$PQ = 1.2$ cm