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If in two triangles ABC and DEF, $\frac{AB}{EF} = \frac{BC}{DE} = \frac{CA}{DF}$; then
- (a)$\triangle DEF \sim \triangle BCA$
- (b)$\triangle ABC \sim \triangle DEF$
- (c)$\triangle DEF \sim \triangle CBA$
- (d)$\triangle ABC \sim \triangle DFE$
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Answer: (B) $\triangle DEF \sim \triangle CBA$