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If in triangles ABC and PQR, $\frac{AB}{QR} = \frac{BC}{PR}$, then they will be similar, when :
- (a)$\angle B = \angle Q$
- (b)$\angle A = \angle R$
- (c)$\angle B = \angle R$
- (d)$\angle C = \angle Q$
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(C) $\angle B = \angle R$