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If $\Delta ABC \sim \Delta PQR$ in which $AB = 6$ cm, $BC = 4$ cm, $AC = 8$ cm and $PR = 6$ cm, then find the length of $(PQ + QR)$.
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$\frac{6}{PQ} = \frac{4}{QR} = \frac{8}{6} \implies PQ = \frac{9}{2}$ cm or $4.5$ cm and $QR = 3$ cm. $\therefore PQ + QR = 7.5$ cm.