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If $\triangle ABC$ and $\triangle DEF$ are similar such that $2 AB = DE$ and $BC = 8$ cm, then $EF$ is equal to :
- (a)$4$ cm
- (b)$8$ cm
- (c)$12$ cm
- (d)$16$ cm
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(d) $16$ cm (1 Mark)
If △ ABC and △ DEF are similar such that 2 AB = DE and BC = 8 cm, then EF is equal to :
CBSE Class 10 Maths PYQ · Triangles · Similarity with Triangles · 1 Mark · March 2026 · Standard
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