Diagonals AC and BD of a trapezium ABCD intersect at O, where AB || DC. If DO/OB = 1/2 , then show that AB = 2CD

CBSE Class 10 Maths PYQ · Triangles · Similarity with Quadrilaterals · 2 Marks · March 2024 · Standard

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1322 Marks · March 2024 · Standard

Diagonals AC and BD of a trapezium ABCD intersect at O, where AB$||$DC. If $\frac{DO}{OB} = \frac{1}{2}$, then show that AB = 2CD

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$\triangle OAB \sim \triangle OCD \Rightarrow \frac{OD}{OB} = \frac{CD}{AB} \therefore \frac{OD}{OB} = \frac{1}{2} \text{ Therefore } \frac{CD}{AB} = \frac{1}{2} \Rightarrow AB = 2 CD$