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ABCD is a trapezium with AB $||$ DC and the diagonals intersect at O. If AO = $(2x + 1)$ cm, OC = $(5x – 7)$ cm, DO = $(7x – 5)$ cm and OB = $(7x + 1)$ cm, then the value of $x$ is :
- (a)$2$
- (b)$3$
- (c)$4$
- (d)$1$
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(A) $2$